# How to Calculate Cement, Sand and Aggregate Quantity?

By | December 20, 2018

In Civil Engineering everywhere ask anyone “How to Calculate Cement, Sand and Aggregate Quantity in Concrete?” Here Give some examples to Calculate Cement, Sand and Aggregate Quantity in Brick Masonry, Concrete work and Plastering.

In Civil Engineering “How to Calculate Cement, Sand and Aggregate Quantity in Concrete?” is very important for field work, Estimate and also interview and competitive exam because its basic of civil engineering.

[A] Brick Masonry:
(i) Number of bricks for 1 m3 of brickwork :
Actual size of brick = 19 cm x 9 cm x 9 cm

Nominal size of a brick = 20 cm x 10 cm x 10 cm (with mortar joint)

For 1 m3 brick masonry

No. of bricks required=(A volume of brickwork / Volume of 1 brick with mortar joint)
= 1 m3/ (0.20 x 0.10 x 0.10) = 500 Nos.

For 1 m3 of brick masonry 500 bricks are required.

(ii) Mortar for 1 m3 of brickwork:
Actual volume of bricks in 1 m3 of brick masonry,
= 500 x (0.19 x 0.09 x 0.09) = 0.77 m3

A volume of wet mortar in 1 ms of brick masonry = 1 – 0.77 = 0.23 m3

For frog filling, cut bricks, for bonding, wastages etc. increase this quantity by 15%.
Volume of wet mortar = 0.23 + (0.15 x 0.23) = 0.264 m3 | Volume of dry mortar reduces by 25% when water is added.

The Volume of dry mortar = 0.264 + (0.25 x 0.264) = 0.33 m3 .

For 1 m3 of brickwork 0.33 m3 of mortar is required.

Materials for 1: 6 brick work

Quantity of brick work = 10 m3

Proportion 1:6

Volume of dry mortar = 3.3 m3

1: 6 = 7  |  C : S
For 1 bag of cement
Weight = 50 kg
Volume = 0.035 m3

Cement =(1/7) x 3.3 = 0.4714 m3

=( 0.4714/0.035) = 13.47 bags
Sand = (6/7) x 3.3 = 2.83 m3

[B] Concrete work:

Based on Concrete strength, concrete is classified into different types of grades like M5, M7.5, M10, M15, M20 etc., M stands for Mix and number stands for characteristic compressive strength of the concrete in 28 days in the direct compressive test. If the ratio for M20 concrete is 1:1.5:3 then 1 part cement, 1.5 part sand and 3 part aggregate (crushed stone) in volume is batched for mixing. We are here calculate M20 concrete is 1:1.5:3 then 1 part cement, 1.5 part sand and 3 part aggregate (crushed stone) in volume by the below-given method.

For 1 m3 of wet compacted concrete, dry volume is taken about 52% more.
1 m3 of wet concrete = 1.52 m3 of dry concrete

quantity of materials for 1 : 1.5 : 3 cement concrete:

Volume of wet concrete = 1 m3

Volume of dry concrete = 1.52 m3

Proportion = 1: 1.5 : 3 (M-20)
C:S:A 1: 1.5 : 3 = 5.5
Cement = (1/5.5) X 1.52 = 0.2763 M3 = (0.2763/ 0.035) = 7.89 say 8 bags

Sand = (1.5/5.5) x 1.52 = 0.414 m3

Aggregate = 5.5 x 1.52 = 0.829 m3

[C] Plastering:
For filling up joints and for uneven surface. To get the dry volume of mortar, a wet volume may be further increased by 25%.

(i) Materials for 100 m2 area and 12 mm thick plaster (1: 4) :

The volume of wet mortar = Area x thickness
= 100 x 0.012 = 1.2 m3
For filling up joints and for an uneven surface, 30% more mortar is required.

The volume of wet mortar = 1.2 x 1.30 = 1.56 m3

To get the dry volume of mortar, a wet volume may be further increased by 25%.
Volume of dry mortar = 1.56 x 1.25 = 1.95 m3 – 2.00 m3

Proportion = 1 : 4 = 5
Cement = 5 x 2 = 0.4 m3 = 0.035 = 11.43 – 11.50 bags
Sand = x 2 = 1.6 m3

(ii) Materials for 100 m2, 1:3, 20 mm thick plaster:

Volume of wet mortar = Area x thickness
= 100 x 0.020 = 2 m3
Here, the thickness of plaster is 20 mm. therefore, mortar required for filling joints and uneven surface, 20% more mortar is required.
The volume of wet mortar = 2 x 1.20 = 2.4 m3

To get the dry volume of mortar, a wet volume may be further increased by 25%.

Volume of dry mortar = 2.4 x 1.25 = 3 m3

Proportion = 1 : 3 = 4
Cement = 4 x 3 = 0.75 m3 = (0.75/0.035) = 21.43 = 21.50 bags
Sand =(3/4) x 3 = 2.25 m3